(3x^2+2x+1)(x^2-4)=0

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Solution for (3x^2+2x+1)(x^2-4)=0 equation:


Simplifying
(3x2 + 2x + 1)(x2 + -4) = 0

Reorder the terms:
(1 + 2x + 3x2)(x2 + -4) = 0

Reorder the terms:
(1 + 2x + 3x2)(-4 + x2) = 0

Multiply (1 + 2x + 3x2) * (-4 + x2)
(1(-4 + x2) + 2x * (-4 + x2) + 3x2 * (-4 + x2)) = 0
((-4 * 1 + x2 * 1) + 2x * (-4 + x2) + 3x2 * (-4 + x2)) = 0
((-4 + 1x2) + 2x * (-4 + x2) + 3x2 * (-4 + x2)) = 0
(-4 + 1x2 + (-4 * 2x + x2 * 2x) + 3x2 * (-4 + x2)) = 0
(-4 + 1x2 + (-8x + 2x3) + 3x2 * (-4 + x2)) = 0
(-4 + 1x2 + -8x + 2x3 + (-4 * 3x2 + x2 * 3x2)) = 0
(-4 + 1x2 + -8x + 2x3 + (-12x2 + 3x4)) = 0

Reorder the terms:
(-4 + -8x + 1x2 + -12x2 + 2x3 + 3x4) = 0

Combine like terms: 1x2 + -12x2 = -11x2
(-4 + -8x + -11x2 + 2x3 + 3x4) = 0

Solving
-4 + -8x + -11x2 + 2x3 + 3x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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